Answer:
Solution,
AB (p) = 11 cm
BC (b) = 4 cm
AC (h) = ?
now,
Using the Pythagoras theorem:
[tex] {h}^{2} = {p}^{2} + {b}^{2} [/tex]
[tex] {h}^{2} = {(11)}^{2} + {(4)}^{2} [/tex]
[tex] {h }^{2} = 121 + 16[/tex]
[tex] {h }^{2} = 137[/tex]
[tex]h = \sqrt{137} [/tex]
[tex]h = 11.70 \: cm[/tex]
Hope this helps...
Good luck on your assignment..