Find the equation of the line through point (−7,2) and parallel to y=25x−12. Use a forward slash (i.e. "/") for fractions (e.g. 1/2.

Respuesta :

parallel line so gradient stays the same at 25x

y=25x+c

substitute in the point

-7= 25(2) +c

-7 = 50 + c

(-7)-50= -57

y=25x-57

hope this helps!

The equation of the line in slope intercept form is y = 25x + 177.

What is equation of a line?

The equation of a line means an equation in x and y whose solution set is a line in the (x,y) plane. The standard form of equation of a line is ax + by + c = 0. Here a, b, are the coefficients, x, y are the variables, and c is the constant term.

For the given situation,

The equation is y = 25x−12 -------- (1)

The point is (−7,2)

The general form of equation of line in slope intercept form is

[tex]y=mx+c[/tex]

On comparing this equation with equation, we get

slope, m = 25

The given line is parallel to the equation of line, so slope is same.

The line passes through the point (x1, y1) is (−7,2).

Thus the equation of line in slope intercept form is

[tex]y-y1=m(x-x1)[/tex]

⇒ [tex]y-2=25(x-(-7))[/tex]

⇒ [tex]y-2=25(x+7)[/tex]

⇒ [tex]y-2=25x+175[/tex]

⇒ [tex]y=25x+175+2[/tex]

⇒ [tex]y=25x+177[/tex]

Hence we can conclude that the equation of the line in slope intercept form is y = 25x + 177.

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