contestada

13
Select the correct answer.
What is the standard form of this function?
Rx) = -(x-4)²+2
OA
Rx) = x2 + 8x-14
OB.
Ax) = x2 + 4x - 30
OC.
RX) = -x2 + 4x - 30
OD
AX) = -x2 + 8x - 14

Respuesta :

unicorn3125

Answer:

             D.    [tex]\bold{\ -x^2+8x-14\ }[/tex]

Step-by-step explanation:

[tex]-(x-4)^2+2=-(x-4)(x-4)+2 = -(x^2-4x-4x+16)+2 = \\\\=-(x^2-8x+16)+2=-x^2+8x-16+2=\underline{\ -x^2+8x-14\ }[/tex]

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