please help!
The equation of line AG is y=(b/a+c)x. The midpoint of BC is (a+c,b). Does the midpoint of BC lie on AG? Why or why not?

•no because (b/a+c)b does not equal a+c
•no because (b/a+c)(a+c) does not equal b
•yes because (b/a+c)b=a+c
•yes because (b/a+c)(a+c)=b

please help The equation of line AG is ybacx The midpoint of BC is acb Does the midpoint of BC lie on AG Why or why not no because bacb does not equal ac no bec class=