In the diagram, what is the perimeter of polygon $PQRST$?

Answer:
24
Step-by-step explanation:
PQ is equal to QR, therefore QR=3
Draw a perpendicular line down from R to line TS to form a triangle and since PT=6, the height of the right angle triangle would be 3.
The base of the right triangle would be 7-3=4. Using pytag. theorem [tex]\sqrt{4^{2}+3^2 }=5[/tex]
Therefore RS=5.
So now we can sum up everything: PQ+PT+TS+RS+QR= 3+6+7+5+3=24