The isosceles triangle and the square shown here have the same area in square units. What is the height of the triangle, $h$, in terms of the side length of the square, $s$?

Answer:
h = 2s
Step-by-step explanation:
Area of square is equal to the area of triangle in this question.
the area of the square is s²
the area of the triangle is [tex]\frac{1}{2}[/tex] *h*s
s²= [tex]\frac{1}{2}[/tex] *h*s
s = [tex]\frac{1}{2}[/tex] *h
2s = h
hope that helps