Answer:
(–4, –8) im positive
Step-by-step explanation:
plz give brainliest
The point (-4, -8) is on the line that passes throgh point R and perpendicular to line PQ option (B) is correct.
A straight line is a combination of endless points joined on both sides of the point.
The slope 'm' of any straight line is given by:
[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have:
Line P Q goes through (-6, 4) and (4, -4).
Point R is at (4, 2).
To find the point on the line that passes through (4, 2) and is perpendicular to line PQ.
First, calculate the slope of the line PQ:
[tex]\rm m =\dfrac{-4-4}{4-(-6)}[/tex]
m = -8/10
m = -4/5
The slope of the perpendicular to the line PQ:
M = -(1/m)
M = 5/4
The equation of the line has a slope 5/4 and passes through point R
y - 2 = (5/4)[x - 4]
Plug x = -4
y = -8
-8 - 2 = (5/4)[-4 - 4]
-10 = (5/4)[-8]
-10 = -10 (true)
Thus, the point (-4, -8) is on the line that passes throgh point R and perpendicular to line PQ option (B) is correct.
Learn more about the straight line here:
brainly.com/question/3493733
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