Jacklou
contestada

how many years it take for a $400 investment to grow to $1000 with a interest rate of 12%/a compounded monthly?

Respuesta :

Answer: 7.674 years

Step-by-step explanation:

A = p (1+r/n)^nt

1000 = 400 (1 + 0 .12/12)^12t

1000 = 400 (1.01)^12t

400 x 1.01^12t = 1000

1.01^12t = 5/2

t = 7.67387

The investment will take 7.6 years to grow to the desired amount with the preferred interest rate, compounded monthly.

Compound Interest:

Compound interest is the interest calculated on the principal and the interest accumulated over the previous period.

According to the given problem,

The formula for measuring compound interest:

[tex]A = P(1+\frac{r}{n} )^{nt}[/tex]  .. (1)

Where, P = Principal

             A = Amount

              r = Interest rate

              n = Number of times interest is compounded in one year

               t = time( years )

Putting values in equation (1),

A = $1000

P = $400

r = 12%

n = 12 (compounded monthly)

⇒ [tex]1000 = 400(1+\frac{0.12}{12})^{nt}[/tex]

⇒ [tex]1000 = 400(1.01)^{12t}[/tex]

⇒ t = 7.6 years

Hence, we can conclude that the amount will take 7.6 years to grow to $1000 at 12% interest rate.

Learn more about compound interest here: https://brainly.in/question/32628013

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