40 POINTS! Please HELP!!!Use the function f(x) to answer the questions:
f(x) = 5x^2 + 2x - 3
Part A: What are the x-intercepts of the graph of f(x)? Show your work (2 points)
Part B: Is the vertex of the graph of f(x) going to be a maximum or a minimum? What are the coordinates of the vertex? Justify your answers and show
your work (3 points)
Part 2: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph (5 points)

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Space Space · Answer 1 · 2020-07-18T17:17:26+02:00

Answer:

Part A: (-1, 0), (0.6, 0)

Part B: Minimum, (-0.2, -3.2)

Part 2: We would find the 3 points: the 2 zeros and the vertex and we would be able to graph.

Step-by-step explanation:

Easiest and fastest way to answer these questions is to graph the equation in a graphing calc.

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goldsk8star goldsk8star · Answer 2 · 2020-07-18T18:38:00+02:00

Eq. [tex]5x^2 + 2x - 3[/tex]

Part A:

1. Set the output value [tex]f(x)[/tex] (also known as "y" on a coordinate plane) = 0

2. [tex]5x^2 + 2x - 3[/tex] = 0

3. Factor using "ac" method. (5 x 3 = 15, what factors of 15 when added/subtracted = 2?)

4. Use zero property.

OR

5. These are the x-intercepts: (3/5, 0) and (- 1, 0)

Part B:

Vertex Formula: x = -b/2a

In a quadratic equation the base equation (standard form) is ax^2 + bx + c, where a is a non-zero constant, and b and c are real numbers.

(eq. 5x^2 + 2x - 3)

-2/2(5) = -2/10 = - 1/5 --> x-coordinate

plug (- 1/5) in for x to get - 16/5 as the y-coordinate.

VERTEX: (-1/5, - 16/5) ; minimum because "a" value is positive