Answer:
0.03 Joules have been converted into other forms of energy as the direct result of the collision.
Explanation:
Let's start studying the conservation of momentum for the system:
[tex]P_i=P_f\\(0.25\,kg)\,{0.6\,m/s)+(0.5\,kg)\,(0\,m/s)=(0.25\,kg+0.5\,kg)\, v_f \\\\\\ 0.15\,kg\,m/s=0.75\,kg\,\,v_f\\v_f=0.15/0.75\,\,m/s\\v_f=0.2\,\,m/s[/tex]
Now that we know the speed of the newly created object, we can calculate how the final kinetic energy differs from the initial one:
[tex]K_i=\frac{1}{2} (0.25)\,(0.6)^2+\frac{1}{2} (0.5)\,(0)^2=0.045\,\,J\\ \\K_f=\frac{1}{2} (0.75)\,(0.2)^2=0.015\,\,J\\[/tex]
Then, when we subtract one from the other, we can estimate how much kinetic energy has been converted into other forms of energy in the collision:
0.045 J - 0.015 J = 0.03 J
