Answer:
[tex]\boxed{\sf \ \ \ g^{-1}(x)=\sqrt{\dfrac{x+5}{3}} \ \ \ }[/tex]
Step-by-step explanation:
Hello,
[tex]x=(gog^{-1})(x)=g(g^{-1}(x))=3(g^{-1}(x))^2-5\\\\<=>3(g^{-1}(x))^2 = x+5\\\\\\<=> (g^{-1}(x))^2=\dfrac{x+5}{3}\\<=>g^{-1}(x)=\sqrt{\dfrac{x+5}{3}}[/tex]
hope this helps
Answer: i think its -3x^2 + 5
Step-by-step explanation:
inverses are when you switch the negates, so i'm assuming you switch them.
sorry if i am wrong !
