Answer:
initial speed (u) = 0.8 m/s
acceleration (a) = 0.2 m/s/s
time (t) = 1.3 min OR 1.3*60 seconds
= 78 seconds
we will use the second equation of motion to find the distance
distance (s) = ut + 1/2 a(t^2)
s = 0.8 * 78 + 1/2 * 0.2 * (6084)
s = 62.4 + 608.4
s = 670.8 m
