Answer:
The significance level for this case would be [tex]\alpha=1-0.95=0.05[/tex] and the critical value for this case would be:
[tex] z_{\alpha/2}=1.96[/tex]
The margin of error is given by:
[tex] ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]
And replacing we got:
[tex] ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683[/tex]
And the margin of error for this case would be [tex] ME = 0.07[/tex]
Step-by-step explanation:
For this case we have the following dataset given:
[tex] n= 146[/tex] represent the sample size
[tex] \hat p =0.23[/tex] represent the estimated proportion of interest
[tex] Conf=0.95[/tex] represent the confidence level
The significance level for this case would be [tex]\alpha=1-0.95=0.05[/tex] and the critical value for this case would be:
[tex] z_{\alpha/2}=1.96[/tex]
The margin of error is given by:
[tex] ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]
And replacing we got:
[tex] ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683[/tex]
And the margin of error for this case would be [tex] ME = 0.07[/tex]
