Answer:
Step-by-step explanation:
Given the functions z= (x+4y)e^y, x=u, and y =ln(v)
To get ∂z/∂u and ∂z/∂v, we will use the the composite rule formula:
∂z/∂u = ∂z/∂x•dx/du + ∂z/∂y•dy/du
∂z/∂x means we are to differentiate z with respect to x taking y as constant and this is gotten using product.
∂z/∂x = (x+4y)(0)+(1+4y)e^y
∂z/∂x = (1+4y)e^y
dx/du = 1
∂z/∂y = (x+4y)e^y+(x+4)e^y
dy/du = 0
∂z/∂u = (1+4y)e^y • 1 + 0
∂z/∂u = (1+4y)e^y
For ∂z/∂v:
∂z/∂v = ∂z/∂y• dy/dv
∂z/∂y = (x+4y)e^y+(x+4)e^y •(1/v)
∂z/∂y = {xe^y+4ye^y+xe^y+4e^y}•(1/v)
∂z/∂y = 2xe^y/v+4e^y(y+1)/v
