Answer:
b. 3p-2q
Step-by-step explanation:
Let the position vector of P=p
Let the position vector of Q=q
Point R divides segment PQ in ratio 3:2 externally.
[tex]\text{Position Vector of R }=\dfrac{\text{(Position Vector of P)m }-\text{(Position Vector of Q) n}}{m-n}[/tex]
m:n = 3:2
Therefore:
[tex]\text{Position Vector of R }=\dfrac{3p -2q}{3-2}\\=3p-2q[/tex]
