Respuesta :

bekkarmahdi702

Answer:

Let's start first with sin(x+y) :

  • sin(x+y)
  • sin(x)*cos(y)+cos(x)*sin(y)

Now with sin(x)+sin(y) :

  • sin(x)+sin(y)
  • 2*sin[(x+y)/2] * cos[(x-y)/2]

We can see that both expressions are far away from being equal

ijustwantmydimitripi

Hi! :D

Not gonna lie, I just copied and pasted in the above answer, and the glossary definitions. Got 100%!

Hope this helps! :)

(P.S. You can find the glossary definitions on the side of the screen using the plus button. If you're ever unsure about your answer, copy them in there!)

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