Answer: magnitude of the impulse of this force is 0.384 Ns
Explanation:
Given the following :
Pushing force (F) = 12N
Duration of the force = time (t) = 32ms, hence, time = 32 × 10^-3 seconds
The impulse of a body is given by the product of the force and the duration of the applied force ;
Therefore impulse = F × t
Impulse = 12 (N) × (32 × 10^-3) (s)
Impulse = 384 × 10^-3
Impulse = 0.384 Ns
