Answer:
a) h_max = 5.10m
b) v = 0.2 m/s
Explanation:
a) In order to calculate the maximum height reached by the rock, you use the following formula:
[tex]h_{max}=\frac{v_o^2}{2g}[/tex] (1)
vo: initial speed of the rock = ?
g: gravitational acceleration constant = 9.8m/s^2
You replace the values of the parameters in the equation (1):
[tex]h_{max}=\frac{(10m/s)^2}{2(9.8m/s^2)}=5.10m[/tex]
The maximum height reached by the rock is 5.10m
b) The speed of the rock, one second after it was thrown is given by:
[tex]v=v_o-gt\\\\v=10m/s-(9.8m/s^2)(1s)=0.2\frac{m}{s}[/tex]
The speed of the rock is 0.2m/s
