Consider the following reversible reaction.
C(s) + O2(g) C02(9)
What is the equilibrium constant expression for the given system?
[CO]
o kor" (CO2)
[CO]
o KooTO]
[C]O2]
o Keg"
[CO2]
[02]
o Ker-1002]

Respuesta :

Answer: The equilibrium constant expression for the given system is [tex]K_{eq}=\frac{[CO_2]}{[O_2]}[/tex]

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric coefficients. It is represented by [tex]K_{eq}[/tex]

For a general chemical reaction:

[tex]aA+bB\rightarrow cC+dD[/tex]

The [tex]K_{eq}[/tex] is written as:

[tex]K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}[/tex]

The concentration of pure solid and pure liquid are taken as 1 in equilibrium expression.

The [tex]K_{eq}[/tex] for the given reaction is written as:

[tex]C(s)+O_2(g)\rightarrow CO_2(g)[/tex]

[tex]K_{eq}=\frac{[CO_2]}{[O_2]}[/tex]

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE