Answer:
0
Step-by-step explanation:
we can use difference of squares to factor the equation into (x+y)(x-y)/(x-y)
The (x-y) cancel out so the fraction becomes (x+y)
The two (x+y) also cancel out so it becomes 0
[tex]x+y-\dfrac{x^2-y^2}{x-y}= \\\\\\x+y-\dfrac{(x+y)(x-y)}{x-y}= \\\\\\x+y-(x+y)= \\\\\\\boxed{0}[/tex]
Hope this helps!
