sammygirl73 sammygirl73

19-06-2020
Mathematics

contestada

Solve: 4x^-2 – 3x^-1– 1 = 0

Respuesta :

mhanifa mhanifa

03-09-2020

Answer:

1, -4

Step-by-step explanation:

4x^-2 – 3x^-1– 1 = 0

Let x^-1 = 1/x = y

4y^2 - 3y - 1 = 0
4y^2 - 4y + y - 1 = 0
(y - 1) (4y + 1) = 0

1. Root 1

y - 1 = 0
y = 1
1/x= 1
x = 1

2. Root 2

4y + 1 = 0
4y = -1
y = -1/4
1/x = - 1/4
x = -4

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