Answer:
20 ml.
Explanation:
molarity of LioH (M1)=2.5M
Volume of LioH( V1)=?
Normality of LiOH (N1)=M1×valence factor=2.5×1=2.5 N
Volume of acid H2SO4(V2)=25 ml
molarity of acid H2SO4(M2)=1.0 M
Normality of acid H2SO4(N2)=M2×valance factor=1.0×2=2.0
now,according to normality equation,
V1.N1=V2.N2
or,V1×2.5=25×2
or,V1=50/2.5
or,V1=20 ml
Therefore, V1=20 ml.
