Please help! Correct answer only, please! Consider the matrix shown below: Find the inverse of the matrix A: (i.e Find A^-1).

Answer: a)
Step-by-step explanation:
Matrix multiplication is the sum of Row 1 (of first matrix) x Column 1 (of second matrix) ...repeat for each row.
Transpose means to switch the rows to columns.
[tex]A=\left[\begin{array}{cc}5&2\\3&-1\end{array}\right] \qquad \times \qquad A^T=\left[\begin{array}{cc}5&3\\2&-1\end{array}\right] \\\\\\= \left[\begin{array}{cc}5(5)+2(2)&5(3)+2(-1)\\3(5)+(-1)(2)&3(3)+(-1)(-1)\end{array}\right] \\\\\\= \left[\begin{array}{cc}29&13\\13&10\end{array}\right][/tex]