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he Punnett square shows the cross for a particular trait between a homozygous dominant parent and a heterozygous parent. What is the probability the offspring will be heterozygous for this trait? 25% 50% 75% 100%

Respuesta :

xxamari

Answer:

50%

Explanation:

Let's make a Punnett square to represent this, with X representing our dominant allele and x our recessive.

One homozygous dominant parent = XX

One heterozygous parent = Xx

      X    X

X   XX  XX  

x    Xx  Xx

So two out of our four outcomes are heterozygous for the trait. That means the answer is B. 50%.

marmar58

Answer:

the answer your looking for is B

Explanation:

50%

its correct on edg2020

hope this helps and the guy that explained this got some brain skills bccc....

hope this helps :)

spot the difference

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