Answer:
Step-by-step explanation:
The given statement can be translated to
[tex]2(n^{3} +9)[/tex]
Where [tex]n[/tex] is the number.
Notice that "twice" is a general product that must cover the whole sum.
If [tex]n=3=r[/tex], then we solve
[tex]2(n^{3} +9)=2(3^{3}+9 )=2(27+9)=2(36)=72[/tex]
Therefore, the student who got 72, that's the right one.
Answer:
[tex]2( {r}^{3} + 9) \\ 2 ({3}^{3} + 9) \\ 2(27 + 9) \\ 2 \times 36 \\ = 72 \\ [/tex]
Step-by-step explanation:
twice a sum
[tex]2(........)[/tex]
twice a sum of a number cubed and nine
[tex]2( {x}^{3} + 9)[/tex]
evaluated for r =3
[tex]x =r = 3[/tex]
so,
[tex]2( {r}^{3} + 9) \\ 2 ({3}^{3} + 9) \\ 2(27 + 9) \\ 2 \times 36 \\ = 72[/tex]
hope this helps
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