Answer:
8 GRAMS OF OXYGEN WILL BE REQUIRED TO PRODUCE 9 GRAMS OF WATER MOLECULES.
Explanation:
The equation for the reaction is;
2 H + O2 ----> 2 H2O
(H = 1, O = 16)
From the reaction, it can be observed that 1 mole of O2 reacts to form 2 moles of H2O
At STP, using the molar masses of the elememts and compound in the reaction, 32 g of O2 will reacts to form 36 g (18 * 2 g) of H2O
32 g of O2 = 36 g OF H2O
if 9 grams of H2O is produced, the mass of oxygen required to produce it will be:
( 32 * 9 / 36 ) g of O2
= (288 / 36) g
= 8 g of O2
So, 8 grams of Oxygen will be required to produce 9 grams of water.
