Answer:
a = 0 and b = -15
Step-by-step explanation:
Given two complex number Z1=3cispi and z2=5cis(pi/2)
In polar form;
z1 = [tex]3(cos[/tex][tex]\pi+isin\pi)[/tex]
z1 = 3(-1+i0)
z1 = -3+0i
Z2 = [tex]5(cos\frac{\pi}{2} +isin\frac{\pi}{2} )[/tex]
Z2 = 5(0+i)
Z2 = 0+5i
Z1*Z2 = (-3+0i)(0+5i)
Z1*Z2 = 0 - 15i +0i + 0i²
Z1*Z2 = 0-15i
comparing 0-15i with a + bi;
a = 0 and b = -15
