Answer:
[tex]y=\frac{22}{\sqrt{2} }[/tex]
x= 19
Step-by-step explanation:
[tex]sen 45 =\frac{11}{y}[/tex]
[tex]y=\frac{11}{sen 45}[/tex]
[tex]y= \frac{11}{\frac{\sqrt[]{2} }{2} }[/tex]
[tex]y=\frac{22}{\sqrt{2} }[/tex]
[tex]y^{2} =x^{2} +11^{2}[/tex]
[tex]x^{2} =y^{2}-121[/tex]
[tex]x^{2}= (\frac{22}{\sqrt{2} }) ^{2} + 121[/tex]
[tex]x^{2} = \frac{484}{2} +121[/tex]
[tex]x^{2} =242+121[/tex]
[tex]x=\sqrt{363}[/tex]
x= 19
