Answer:Specific heat capacity of metal is 2.09 j/g.°C.
Explanation:Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Given data:
Mass of metal = 15.5 g
Initial temperature = 165.0°C
Initial temperature of water = 23.0°C
Final temperature = 30.0°C
Specific heat capacity of metal = ?
Specific heat capacity of water = 4.184 J/g°C
Volume of water = 150.0 mL or 150.0 g
Solution:
Formula:
- Qm = +Qw
Now we will put the values in formula.
-15.5 g × c × [ 30.0°C - 165.0°C] = 150 g × 4.184 J/g°C × [ 30.0°C - 23.0°C]
15.5 g × c × 135°C = 4393.2 j
2092.5 g.°C × c = 4393.2 j
c = 4393.2 j/2092.5 g.°C
c = 2.09 j/g.°C
