iyana14avery iyana14avery

19-05-2020
Physics

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A woman is pushing a 38.7kg lawnmower initially at rest with a 68.7N forward force against friction. The lawnmower speeds up to 1.44m/s in 3.81s. How much force does friction evert on the mower

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19-05-2020

Answer:

expected acceleration= 68.7/38.7=1.77 m/s^2

witnessed acceleration = 1.44/3.81 = 0.37 m/s^2

difference = 1.4m/s^2

so friction = 38.7× 1.4= 54.18 N

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llamadude0324 llamadude0324

19-01-2022

Answer:

54.18

Explanation:

54.18 works for acellus

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