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A scooter has a mass of 250. Kg. A constant force is exerted on it for 60.0 S. during the time the force is exerted, the scooter increases its speed from 6.00 m/s to 28.0 m/s. What is the change in momentum? What is the magnitude of the force exerted on the scooter?

Respuesta :

Answer:

Explanation:

change in momentum = m ( v - u )   ;   m is mass , V is final velocity and u is initial velocity .

= 250 ( 28 - 6 )

= 5500. N.s

for calculating magnitude of force we shall apply the concept of impulse

Impulse = F X t = m( v-u )    ;   F is force applied for time t .

F x 60 = 5500

F = 91.67 N .

force exerted = 91.67 N .

Change in momentum is 5500 N/S

The magnitude of the force exerted on the Scooter is 91.67 N

The calculation can be done as follows

The formula for change in momentum is;

m(v-u)

250(28-6)

250(22)

5500 N/S

The formula for magnitude of the force is

F ˣ 60= 5500

F= 5500/60

F= 91.67 N

Hence the magnitude of force is 91.67 N and the change in momentum is 5500 N/S

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https://brainly.com/question/19603494?referrer=searchResults

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