Answer:
area of BMDN 8 ft²
Step-by-step explanation:
In BMDN the diagonals are BD and MN.
MN is 12/3 = 4 ft long, and BD = 4 ft.
A rhombus with equal diagonals is a square, so BMDN is a square.
In the right triangle BDN, the diagonal BD is the hypotenuse, then:
DN² + NB² = BD²
but DN = NB, then:
2*DN² = 16 ft²
DN² = 8 ft²
The area of BMDN is computed as one of its sides squared. Then, DN² is its area
