Answer: Thus the volume of the container that the gas is in 2311 L
Explanation:
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = 0.09 atm
V = Volume of gas = Volume of container = ?
n = number of moles = 7.7
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]56^0C=(56+273)K=329K[/tex]
[tex]V=\frac{nRT}{P}[/tex]
[tex]V=\frac{7.7mol\times 0.0821Latm/K mol\times 329K}{0.09atm}=2311L[/tex]
Thus the volume of the container that the gas is in 2311 L
