Serenity invested $16,000 in an account paying an interest rate of 4.5% compounded annually. Assuming no deposits or withdrawals are made, how much money, to the nearest hundred dollars, would be in the account after 9 years?

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Answer:

A ≈ 23800

Step-by-step explanation

The amount, to the nearest hundred dollars, that would be in the account of Serenity after 9 years for the considered situation is $20,836.162

How to calculate compound interest's amount?

If the initial amount (also called as principal amount) is P, and the interest rate is R% per unit time, and it is left for T unit of time for that compound interest, then the interest amount earned is given by:

[tex]CI = P(1 +\dfrac{R}{100})^T - P[/tex]

The final amount becomes:

[tex]A = CI + P\\A = P(1 +\dfrac{R}{100})^T[/tex]

For this case, we're specified that:

  • Initial amount that was deposited =  P = $16,000
  • Rate of interest = R = 4.5 (in percent) annually (compount interest)
  • So, unit of time = 1 year.
  • Number of units of time for which money was invested = 9 (years).

Thus, we get the final amount in the account of Serenity after 9 years as evaluated by:

[tex]A = P(1 +\dfrac{R}{100})^T\\\\A = 16000 \times\left(1+\dfrac{4.5}{100}\right)^6 = 16000 \times (1.045)^6\\\\A = 20836.162 \: \rm dollars[/tex]

Thus, the amount, to the nearest hundred dollars, that would be in the account of Serenity after 9 years for the considered situation is $20,836.162

Learn more about compound interest here:

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