Respuesta :
Answer:
[tex]z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462[/tex]
Now we can find the p value using the alternative hypothesis with this probability:
[tex]p_v =P(z>0.462)=0.322[/tex]
Since the p value is large enough, we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%
Step-by-step explanation:
Information provided
n=100 represent the random sample selected
[tex]\hat p=0.77[/tex] estimated proportion of students that are satisfied
is the value that we want to test
z would represent the statistic
[tex]p_v[/tex] represent the p value
System of hypothesis
We want to verify if more than 75 percent of his customers are very satisfied with the service they receive, then the system of hypothesis is.:
Null hypothesis:[tex]p\leq 0.75[/tex]
Alternative hypothesis:[tex]p > 0.75[/tex]
The statistic is given by:
[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)
Replacing the info given we got:
[tex]z=\frac{0.77-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}=0.462[/tex]
Now we can find the p value using the alternative hypothesis with this probability:
[tex]p_v =P(z>0.462)=0.322[/tex]
Since the p value is large enough we have evidence to conclude that the true proportion for this case is NOT significanctly higher than 0.75 since we FAIL to reject the null hypothesis at any significance level lower than 30%
