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An aqueous feed solution of 1000 kg/h containing 23.5 wt % acetone and 76.5 wt % water is being extracted in a countercurrent multistage extraction system using pure methylisobutyl ketone solvent at 298–299 k. the outlet water raffinate will contain 2.5 wt % acetone. use equilibrium data from

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Question:

The question is incomplete. What is required to calculate was not added.The equilibrium data was not also added. Below is the additional questions and the answers.

1. Calculate the minimum solvent that can be used.

2.Using a solvent rate of 1.5 times the minimum, calculate the number of

theoretical stages.

Answer:

1. Minimum solvent = 411.047

2. N = 5

Explanation:

See the attached files for explanations.

Ver imagen gbenewaeternity
Ver imagen gbenewaeternity
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Ver imagen gbenewaeternity
Ver imagen gbenewaeternity

An aqueous feed solution.

The aqua solution is a solvent on water that has a chemical equation of aq. The example includes the solution of the salt table and NaCl. Having positive and negative ions. The solution feed id of 1000 KG/hand consists of 23.5 wt% acetone and has a 76.5 wt% of water by volume which is being used.

Thus the answer is minimum solvent = 411.047 and the N equals 5.

  • The 76.5wt of water is extracted in a concurrent multistage of the extraction system and is used with the methyl isobutyl.
  • With the ketone solvent at the temperature of 298-299K. The outer or output of 2.5 wt 5 acetone which is a colorless liquid gets dissolved.
  • Hence the answer is a mini solvent of 411.0 and value of N as 5.

Learn more about the aqueous feed solution.

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