Answer:
The answer is false
Explanation:
The given reaction is
[tex]Br_{2}_{(l)} + Mn^{2+}_{(aq)} ------->MnO_4 _{(aq)} + Br^-_{(g)}[/tex]
At the cathod the potential is
[tex]E_{cath} = + 1.065V[/tex] [This because it will attract the negative
charge]
At the Anode the potential is
[tex]E_{anode} = 1.51[/tex]
The overall potential of the cell is
[tex]E_{cell} = E_{cath} - E_{anode}[/tex]
[tex]= -0.445[/tex]
Since the potential of the cell is less than 0 then the reaction is not spontenous under standard condition
The reaction below is spontaneous under standard conditions should be considered false.
Since the given reaction is br2(l) + mn2+(aq) → mno4-(aq) + br-(g)
Also, at the anode, the potential should be
Eanode = 1.51
And, the overall potential of the cell is
= -0.445
Also, the potential of the cell should be lower than 0 so the reaction is not spontenous under standard condition
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