Answer:
- Area of Circle A[tex]=9 \pi[/tex]
- Area of Circle B[tex]=49 \pi[/tex]
- Area of Circle C[tex]=121 \pi[/tex]
- Area of Circle D[tex]=64 \pi[/tex]
- The area of circle D is [tex]7\frac{1}{9}[/tex] times greater than the area of circle A.
Step-by-step explanation:
Circle A
The radius of circle A is 3 in
r= 3 Inch
Area of Circle A[tex]=\pi r^2=3^2*\pi=9 \pi[/tex]
Circle B
The radius of circle B is 4 inch greater than circle A.
r= 4+Radius of circle A= 4+3 =7 Inch
Area of Circle B[tex]=\pi r^2=7^2*\pi=49 \pi[/tex]
Circle C
The radius Circle C is 4 in greater than circle b.
r= 4+Radius of circle B= 4+7 =11 Inch
Area of Circle C[tex]=\pi r^2=11^2*\pi=121 \pi[/tex]
Circle D
The radius of circle D is 3 in less than the radius of circle C.
r= Radius of circle C -3 = 11-3 =8 Inch
Area of Circle D[tex]=\pi r^2=8^2*\pi=64 \pi[/tex]
Area of Circle A[tex]=9 \pi[/tex]
Area of Circle D[tex]=64 \pi[/tex]
Number of Times by which Area of Circle D is greater than Area of Circle A
=[tex]\frac{64 \pi}{9 \pi} =7\frac{1}{9}[/tex]
- The area of circle D is [tex]7\frac{1}{9}[/tex] times greater than the area of circle A.
