Answer:
Step-by-step explanation:
hello :
use equation for this circle : the center is : O(0,0)
the radius is 13
let (∆) this tangent in A(5,12) where an equation is : y-y1 = m(x-x1)
x1 = 5 and y1 =12 calculate : m the slope of this tangent
but (∆) tangent in A(5,12) for this circle : means the line (OA)⊥tangent(∆)
the slope of (OA)×m = -1
but the slope of (OA)= (12-0)/(5-0)=12/5
(12/5)×m =-1 so : m=-5/12
an equation for this tangent is y-12 = (-5/12)(x-5)
