Answer:
Let the width of the poster = X inches
SO, the length of the poster = X+6 inches
Let the perimeter of the rectangular poster = 188 inches
Step-by-step explanation:
x+X+6 = 188
2x+6 = 188
transfer + 6 to right side
2x = 188-6
2x = 182
X = 182/2
X = 91
[tex]x = \frac{182}{2 } = 91[/tex]
The area of the rectangular poster whose perimeter is 188 inches and length 6 inches longer than its width is 2200 sq. inches.
It is obtained by assuming width as b and length as b+6, putting in the formula of perimeter of rectangle and finding values of length and width.
Let width of the rectangle be b.
Then, length of the rectangle will be b+6.
Perimeter of a rectangle = 2(l+b)
2(l+b) = 188
2(b+6+b) = 188
2(2b+6) = 188
4b+12 = 188
4b = 188-12
b = 176/4 = 44
Hence, length = b+6 = 44+6 = 50 inches
Width = 44 inches
Area of a rectangle = l × b
= 50×44
=2200 sq. inches.
Therefore, area of the rectangular poster is 2200 sq. inches.
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