Answer:
B. (4x^2 + 2)(x - 3)
Step-by-step explanation:
4x^3 - 12x^2 + 2x - 6
Factor by grouping
4x^3 - 12x^2 + 2x - 6
Factor 4x^2 out of the first group and 2 out of the second group
4x^2 (x-3) +2(x-3)
Now factor out (x-3)
(x-3) (4x^2 +2)
To factor completely we should factor out a 2
(x-3) 2 (2x^2 +1)
2 (x-3 )(2x^2+1) but since this is not one of the choices, go with B
