Answer:
We need 113000 J of heat (option 2 is correct)
Explanation:
Step 1: Data given
Mass of liquid water = 50.0 grams
ΔHVap = 2260 J/g
Temperature = 100 °C
ΔHVap = The amount of heat released to change phase of a liquid water to steam = 2260 J/g
Step 2: Calculate the heat needed
Q =m* ΔHVap
⇒with Q = the amount of heat needed = TO BE DETERMINED
⇒with m = the mass of water = 50.0 grams
⇒with ΔHVap = 2260 J/g
Q = 50.0 grams * 2260 J
Q = 113000 J
We need 113000 J of heat (option 2 is correct)
