To prepare 2 M of solution, if 2.5 moles of solute is present then the needed amount of volume is 1.25 L.
Molarity of any solution define as the number of moles of solute present in per liter of the solution, i.e.
M = n/V
Given that, moles of solute = 2.5 moles
Molarity of solution = 2 M
Volume will be calculated as:
V = 2.5 / 2 = 1.25 L
Hence required volume of solution is 1.25 L.
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