Answer:
6; solution is not extraneous
Step-by-step explanation:
[tex]\sqrt{3x-2} =4[/tex]
[tex](\sqrt{3x-2})^{2} = (4)^2[/tex]
[tex]3x-2= 16[/tex]
[tex]3x = 18[/tex]
[tex]x =6[/tex]
[tex]\sqrt{3(6)-2}=4[/tex]
[tex]\sqrt{18-2}=4[/tex]
[tex]\sqrt{16} =4[/tex]
[tex]4=4[/tex]
6; solution is not extraneous
because 4 is equal to 4, an extraneous answer would be the correct answer given, however when you plug it into the equation it is not equal
