Given:
In ΔPQR, ∠Q = 90°
PQ = 8 cm
QR = 15 cm and
PR = 17 cm
To find the value of ∠P.
Formula
By Trigonometric ratio we get,
[tex]tan \theta=\frac{opp}{adj}[/tex]
Now let us take ∠P = θ
With respect to θ, QR be the opposite side and PQ be the adjacent side.
So,
tan θ = [tex]\frac{QR}{PQ}[/tex]
tan θ = [tex]\frac{15}{8}[/tex]
θ = [tex]tan^{-1} (\frac{15}{8} )[/tex]
θ = 61.93° (approx)
Hence, the value of ∠P is 61.93° (approx).
