The length of a rectangular deck is 4 times its width. If the deck's perimeter is 30 feet, what is the deck's area?

[tex]Perimeter\ of\ rectangular\ deck=2width+2lenght\\\\ length=4width\\\\ 30=2width+2(4width)\\\\ 30=2width+8width\\\\ 30=10width\ \ \ \ |divide\ by\ 10\\\\ width=3feet\\\\ Area=width*length\\\\ Area=3*4=\boxed{12feet^2}[/tex]

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gamegirl3596 gamegirl3596 · Answer 2 · 2014-10-18T04:02:06+02:00

gamegirl3596 gamegirl3596

18-10-2014

36 square feet because the width would be a and so since the length is 4 times that you can say that the two sides added together would be 5a
30 feet is the parameter which would include all 4 sides but we are only looking for 2 sides so you can divide that by 2 so
5a=15 so divide 15 by 5 and you get 3 so a=3
4a=4*3= 12=length
a=3=width
length*width=area
12*3= 36 square feet

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