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mariamikayla
[tex]3p-6\ \textgreater \ 21 \\\\ 3p\ \textgreater \ 21+6 \\\\ 3p\ \textgreater \ 27 \ \ \ \ |:3 \\\\ p\ \textgreater \ 9 \\\\ \boxed{p \in (9;\infty) }[/tex]
CharlieBrown2002

Answer:

p>9

Step-by-step explanation:

Add by 6 from both sides of equation.

3p-6+6>21+6

Simplify.

21+6=27

3p>27

Divide by 3 from both sides of equation.

3p/3>27/3

Simplify, to find the answer.

27/3=9

p>9 is the correct answer.

I hope this helps you, and have a wonderful day!

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