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We are asked for the oxidation number of Cr(OH)3. it is  know that upon reaction, the charges of each ionic element are exchanged and reflected on the subscripts. Hence, the oxidation number of Cr (OH)3 is zero since Cr is +3 and that of OH is -1*3 or -3 in total.

Answer : The oxidation number of 'Cr' in [tex]Cr(OH)_3[/tex] is, (+3)

Explanation :

As in the given compound [tex]Cr(OH)_3[/tex], 'Cr' is the chromium metal and [tex]'OH^-'[/tex] is the hydroxide ion. The charge on the hydroxide ion is, (-1)

The given compound is, [tex]Cr(OH)_3[/tex]

Let the oxidation number of 'Cr' be, 'x'

[tex]x+3(-1)=0\\\\x-3=0\\\\x=+3[/tex]

Hence, the oxidation number of 'Cr' in [tex]Cr(OH)_3[/tex] is, (+3)

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