How many valence electrons in Al3+?

Aluminum has an atomic number of 13. The electronic configuration of Al is 1s2 2s2 2p6 3s2 3p1. Al3+ has only 10 electrons so the configuration of Al 3+ is 1s2 2s2 2p6. The highest energy level is 2 so the number of electrons in the highest level is the valence electrons which is 8.

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Annainn Annainn · Answer 2 · 2019-08-13T08:48:23+02:00

Answer:

There will be zero valence electrons in Al3+

Explanation:

Aluminum (Al) belongs to group 13 in the periodic table with atomic number,Z = 13

Atomic number = number of electrons = 13

Based on the Aufbau principle, the 13 electrons can be arranged from the lowest energy orbital to the highest as follows:

Al(Z=13)= 1s²2s²2p⁶3s²3p¹

The valence orbitals are those orbitals which belong to the shell that farthest from the nucleus. In this case the shell corresponds to n = 3. Hence the valence configuration for Al is:

Al (valence electrons) = 3s²3p¹

Therefore, Al has 3 valence electrons.

The given ion is Al³⁺ . The +3 charge indicates a loss of three electrons.

Al³⁺ = 3s⁰3p⁰

Since there are only 3 valence electrons in Al a cation with a +3 charge would result in the loss of all valence electrons.