Write the standard equation for the circle with center (–2, 5) that passes through (1, 9).

A. (x – 2)2 + (y + 5)2 = 5
B. (x + 2)2 + (y – 5)2 = 5
C. (x – 2)2 + (y + 5)2 = 25
D. (x + 2)2 + (y – 5)2 = 25

Respuesta :

All given options are incorrect .. As no one is the equation of a circle
caylus
Hello,

Answer D:

1) we must find the radius:

r²=(1-(-2))²+(9-5à²=3²+4²=9+16=25=5²

The circle's equation  is
(x-(-2))²+(y-5)²=25
or (x+2)²+(y-5)²=25

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE